The New Amateur-Japanese Rules use the concept of "control" to specify scoring intersections. Control relies on a player's ability to establish "immortal" stones, i.e. to fill parts of the board with two-eye-formations. This is simple.
Why is life and death complex while control is
simple? Life and death can be determined hypothetically only; otherwise
filling stones in one's territories would cost points. Hypothetical means
that each theoretically possible move-sequence must be considered. - Control
can be determined practically because each of Black's control and White's
control is determined by only one considered move-sequence. The practically
executed performance allows the players to understand why intersections
are controlled or not controlled.
The only shape in that this rule needs to be applied is the basic ko
shape, which is a ko that consists of two adjacent intersections. A position
might contain several basic kos but the rule becomes relevant only if in
the same basic ko a play captures a stone and then immediately the next
play would recapture that stone.
position with Black to move
. . . . . .
. . # O . .
. # O . O .
. . # O . .
. . . . . .
position after Black play 1
. . . . . .
. . # O . .
. # . # O .
. . # O . .
. . . . . .
position after prohibited White play 2
. . . . . .
. . # O . .
. # O . O .
. . # O . .
. . . . . .
The White play 2, which would capture a stone in the basic ko, is prohibited. It would recreate the position just before the last opposing (black) move 1; this is prohibited by the basic-ko rule. Currently White has to make a different move.
(2)
position with Black to move
# # # # #
. # O # O
# O . O .
O O O O O
position after Black play 1
# # # # #
. # . # O
# O # O .
O O O O O
prohibited play P for White
# # # # #
. # P # O
# O # O .
O O O O O
Currently the basic-ko rule prohibits White to play at the intersection
P. Instead White might play in the left basic ko or pass.
For the rule to apply, some positions must be recreated. Otherwise there
is no possibility that the rule might apply usefully. Recreated positions
are rare; therefore almost always one can ignore the rule entirely. The
following examples show some rare shapes with repetition nevertheless.
position with Black to move
. # # . O
# O O O O
. O # # #
O O # . #
# # # # .
position after Black play 1
. # # . O
# O O O O
# O # # #
O O # . #
# # # # .
position after White play 2
O # # . O
. O O O O
. O # # #
O O # . #
# # # # .
position after Black play 3
. # # . O
# O O O O
. O # # #
O O # . #
# # # # .
The fixed-ko rule does not prohibit Black's play 3: The position before the play 3 and the position before the play 1 are not the same. The rule does not prohibit that the position after the play 3 and the position before the play 1 are the same.
position after White pass 4
. # # . O
# O O O O
. O # # #
O O # . #
# # # # .
The fixed-ko rule applies only to plays, not to passes. Therefore White is not prevented from passing.
position after prohibited Black play 5
. # # . O
# O O O O
# O # # #
O O # . #
# # # # .
The fixed-ko rule prohibits Black's play 5: The position before the play 5 and the position before the play 1 are the same. Furthermore the position after the play 5 and the position after the play 1 are the same. The fixed-ko rule prohibits that both the positions before two plays and the positions after these are the same. In other words, as soon as a position recurs, the next play may not start recycling on the same intersection again.
In practice in the alternation, during the played cycle Black has lost more captured stones than White. Therefore it was a strategic mistake of Black to start the cycle. He might have passed immediately.
(2)
position with Black to move
# # # # #
. # O # O
# O . O .
O O O O O
position after Black play 1
# # # # #
. # . # O
# O # O .
O O O O O
position after White play 2
# # # # #
O # . # O
. O # O .
O O O O O
position after Black play 3
# # # # #
O # . # .
. O # O #
O O O O O
position after White play 4
# # # # #
O # O # .
. O . O #
O O O O O
position after Black play 5
# # # # #
. # O # .
# O . O #
O O O O O
position after White play 6
# # # # #
. # O # O
# O . O .
O O O O O
prohibited plays for Black
# # # # #
. # O # B
# O P O #
O O O O O
Black may not play at B because of the basic-ko rule.
The fixed-ko rule prohibits P because otherwise the positions before the play 1 and before the play 7 at P would be the same and the positions after the play 1 and after the play 7 at P would be the same.
Hence Black passes:
position after Black pass 7
# # # # #
. # O # O
# O . O .
O O O O O
position after White pass 8
# # # # #
. # O # O
# O . O .
O O O O O
Note: Strategically, the fixed-ko rule lets many complex ko shapes
be fixed. Playing a cycle is legal but futile. Black might have passed
with his move 1 and the result would be the same. In a triple ko, generally
the player with initially more ko liberties wins the triple ko.
empty grid
. . . . .
. . . . .
. . . . .
. . . . .
. . . . .
alternation with Black moving first
. . . . .
7 3 1 5 11
8 6 2 4 12
. . 10 . 9
. . . . .
13 = pass, 14 = pass
position at the end of alternation
. . . . .
# # # # #
O O O O O
. . O . #
. . . . .
Result: White wins by 5 points.
. . . . .
# # # # #
O O O O O
. . O . #
. . . . .
intersections scoring for Black B
B B B B B
# # # # #
O O O O O
. . O . #
. . . . .
points per scoring intersection for Black
1 1 1 1 1
# # # # #
O O O O O
. . O . #
. . . . .
Black has 5 points.
intersections scoring for White W
. . . . .
# # # # #
O O O O O
W W O W W
W W W W W
points per scoring intersection for White
. . . . .
# # # # #
O O O O O
1 1 O 1 2
1 1 1 1 1
White has 10 points. The intersection that scores for White and has a black stone on scores 2 points for White.
Score: The score is 5 - 10 = -5, i.e. 5 points for White.
Result: White wins.
The "black-analysis" determines the intersections Black controls. The "white-analysis" determines the intersections White controls.
Now we understand why the process of the game contains the "black-analysis" and the "white-analysis" and why these are in between the alternation and the result. Accordingly the rules define the term "game":
"The game consists of the following in the given order:
In other words, stones of a player are "immortal" if they cannot be
removed even if the opponent makes as many successive legal plays as he
likes.
. # . # O . O # O . # .
# # # # O . O # # # # #
O O O O O . . . . O . .
All black stones are immortal. White, who starts, might try to remove some of them but would fail:
. # . # O . O # O . # .
# # # # O . O # # # # #
O O O O O . . 1 3 O 5 7
The moves 2, 4, 6 are passes. Due to the no-suicide rule White cannot occupy the last liberties of the black stones.
(2)
. . O .
. O O O
The white stones are not immortal. Black, who starts and chooses well, can remove them as follows:
. 1 O 5
3 O O O
The moves 2 and 4 are passes. By the definition of "immortal", White
is obliged to pass. Black succeeds in removing the white stones. Therefore
they are not immortal.
The final-position, i.e. the position at the end of the alternation,
is the one and only position in that the players can control intersections.
It is necessary only in the final-position since that position defines
the score of the game.
The black-analysis determines which intersections are controlled by Black.
During the black-analysis, the players decide their strategy. However,
naturally Black wants to maximize his score on the board while White wants
to minimize Black's score.
In this example, passive strategies are used during the black-analysis.
final-position
. . . . .
# # # # #
O O O O O
. . O . #
. . . . .
black-analysis
4 . 2 . 6
# # # # #
O O O O O
. . O . #
. . . . .
The moves 1, 3, 5, 7, 8, 9 are passes.
position at the end of the black-analysis
# . # . #
# # # # #
O O O O O
. . O . #
. . . . .
Black control B
B B B B B
B B B B B
O O O O O
. . O . #
. . . . .
For Black to control some intersection, Black must have occupied the intersection with an immortal stone or must have immortal stones on each of its adjacent intersections. In other words, to control a region of the board, Black must have filled it with his stones or ponnukis.
application of the Black control for the Black score
1 1 1 1 1
# # # # #
O O O O O
. . O . #
. . . . .
In the position at the end of the black-analysis one sees which intersections Black controls in the final-position. Accordingly such intersections can score for Black in the final-position: 1 point if they are empty, 2 points if they are occupied by white stones.
(2)
In this example, aggressive strategies are used during the black-analysis.
final-position
. . . . .
# # # # #
O O O O O
. . O . #
. . . . .
black-analysis
8 3 1 4 .
# # # # #
O O O O O
7 6 O . #
. 5 2 . .
10 is played at 1. The moves 9, 11, 12, 13 are passes.
position at the end of the black-analysis
# . # # .
# # # # #
O O O O O
O . O . #
. O # . .
Black control B
B B B B B
B B B B B
O O O O O
. . O . #
. . . . .
Black controls the same intersections of the final-position as in
example (1).
The white-analysis determines which intersections are controlled by White.
During the white-analysis, the players decide their strategy. However,
naturally White wants to maximize his score on the board while Black wants
to minimize White's score.
In this example, passive strategies are used during the white-analysis.
final-position
. . . . .
# # # # #
O O O O O
. . O . #
. . . . .
white-analysis
. . . . .
# # # # #
O O O O O
4 . O 8 #
. 6 2 . 10
The moves 1, 3, 5, 7, 9, 11, 12, 13 are passes.
position at the end of the white-analysis
. . . . .
# # # # #
O O O O O
O . O O .
. O O . O
White control W
. . . . .
# # # # #
W W W W W
W W W W W
W W W W W
For White to control some intersection, White must have occupied the intersection with an immortal stone or must have immortal stones on each of its adjacent intersections. In other words, to control a region of the board, White must have filled it with his stones or ponnukis.
application of the White control for the White score
. . . . .
# # # # #
O O O O O
1 1 O 1 2
1 1 1 1 1
In the position at the end of the white-analysis one sees which intersections White controls in the final-position. Accordingly such intersections can score for White in the final-position: 1 point if they are empty, 2 points if they are occupied by black stones.
(2)
In this example, aggressive strategies are used during the white-analysis.
final-position
. . . . .
# # # # #
O O O O O
. . O . #
. . . . .
white-analysis
. . 2 . .
# # # # #
O O O O O
5 6 O 7 #
. 4 1 3 8
intermediate position during the white-analysis
. . O . .
# # # # #
O O O O O
# O O . .
. O . . O
continued white-analysis
. 12O 13.
# # # # #
O O O O O
# O O 1810
14O 169 O
The moves 11, 15, 17, 19, 20, 21 are passes.
position at the end of the white-analysis
. O O # .
# # # # #
O O O O O
. O O O O
O O O . O
White control W
. . . . .
# # # # #
W W W W W
W W W W W
W W W W W
Despite aggressive play by both players, White controls the same
intersections of the final-position as in example (1).
final-position
. . . . .
# # # # #
O O O O O
. . O . #
. . . . .
intersections scoring for Black
1 1 1 1 1
# # # # #
O O O O O
. . O . #
. . . . .
intersections scoring for White
. . . . .
# # # # #
O O O O O
1 1 O 1 2
1 1 1 1 1
Score = 5 - 10 = -5. White has 5 points more than Black.
Result: White wins.
final-position
. . . . .
# # # # #
O O O O O
. . O . #
. . . . .
Suppose that the players start counting using the Japanese counting procedure. They might rearrange the stones as follows:
Japanese counting with some mistake
. . . . .
# # # # #
O O O O O
O . . . .
. . . . .
Now we assume that the players make the mistake of not recalling whether they have already filled in the one black prisoner stone. They disagree. This invokes the disagreement procedure.
Step 1) The normal procedure is interrupted.
The players do not continue with the normal procedure. Instead they start the disagreement procedure.
Step 2) The players restore the final-position and the prisoners at it.
final-position
. . . . .
# # # # #
O O O O O
. . O . #
. . . . .
The players restore the final-position as it arose at the end of the alternation. The players also restore the prisoners, but in this case there have been none that were made during the alternation.
Step 3) The players copy the final-position to two extra boards.
final-position copy 1 copy 2
. . . . . . . . . .
. . . . .
# # # # # # # # # #
# # # # #
O O O O O O O O O O
O O O O O
. . O . # . . O . #
. . O . #
. . . . . . . . . .
. . . . .
Step 4) The players use copy 1 of the final-position to perform the black-analysis.
black-analysis performed on copy 1 of the final-position
. . . . . 4 . 2 . 6
. . . . .
# # # # # # # # # #
# # # # #
O O O O O O O O O O
O O O O O
. . O . # . . O . #
. . O . #
. . . . . . . . . .
. . . . .
The moves 1, 3, 5, 7, 8, 9 are passes.
position at the end of the black-analysis on the copy 1 board
. . . . . # . # . #
. . . . .
# # # # # # # # # #
# # # # #
O O O O O O O O O O
O O O O O
. . O . # . . O . #
. . O . #
. . . . . . . . . .
. . . . .
Step 5) The players use copy 2 of the final-position to perform the white-analysis.
white-analysis performed on copy 2 of the final-position
. . . . . # . # . #
. . . . .
# # # # # # # # # #
# # # # #
O O O O O O O O O O
O O O O O
. . O . # . . O . #
4 . O 8 #
. . . . . . . . . .
. 6 2 . 10
The moves 1, 3, 5, 7, 9, 11, 12, 13 are passes.
position at the end of the white-analysis on the copy 2 board
. . . . . # . # . #
. . . . .
# # # # # # # # # #
# # # # #
O O O O O O O O O O
O O O O O
. . O . # . . O . #
O . O O .
. . . . . . . . . .
. O O . O
Step 6) The players determine the intersections that Black controls in the final-position.
B B B B B # . # . #
. . . . .
B B B B B # # # # #
# # # # #
O O O O O O O O O O
O O O O O
. . O . # . . O . #
O . O O .
. . . . . . . . . .
. O O . O
The intersections B are the intersections that Black controls in the final-position: These are the intersections on or around that Black has got immortal stones in the black-analysis.
Step 7) The players determine the intersections that White controls in the final-position.
. . . . . # . # . #
. . . . .
# # # # # # # # # #
# # # # #
W W W W W O O O O O
O O O O O
W W W W W . . O . #
O . O O .
W W W W W . . . . .
. O O . O
The intersections W are the intersections that White controls in the final-position: These are the intersections on or around that White has got immortal stones in the white-analysis.
Step 8) The players determine the score.
intersections scoring for Black
1 1 1 1 1 # . # . #
. . . . .
# # # # # # # # # #
# # # # #
O O O O O O O O O O
O O O O O
. . O . # . . O . #
O . O O .
. . . . . . . . . .
. O O . O
intersections scoring for White
. . . . . # . # . #
. . . . .
# # # # # # # # # #
# # # # #
O O O O O O O O O O
O O O O O
1 1 O 1 2 . . O . #
O . O O .
1 1 1 1 1 . . . . .
. O O . O
Score = 5 - 10 = -5. White has 5 points more than Black.
Step 9) The players determine the result.
Result: White wins.
Step 10) The players make the result agreement due to the determined result.
The players sign the result form so that White wins the game. (In
some tournaments, the players would mark the correct result on some walllist
rather than signing a result form.)
An often posed question about definitions
of the term "position" is whether rotating or mirroring the board with
otherwise the same distribution of stones creates a different position.
The answer is: yes. The reason is that the rule speaks of "specific" intersections.
Each of the 361 intersections of the grid is unique. (Of course, the rule
text might be more precise and explicit, however, a semi-formal text is
always a compromise between accessibility by the average reader and a mathematician's
desire for ultimate precision.)
The basic-ko rule might have been more explicit about this like the
fixed-ko rule's mentioning of "of the same move-sequence". However, because
of the aforementioned reason in a semi-formal rule text this is not really
necessary.
# # # # #
. # O # O
# O . O .
O O O O O
As we have seen earlier, this will also be the final-position. But why does White not need to remove the black stones during the alternation? This is answered by looking at the black-analysis and the white-analysis: Playing a stone during the alternation would cost 1 point for the score.
black-analysis: White moves first
# # # # #
1 # O # O
# O . O .
O O O O O
The moves 2, 3, 4 are passes.
position at the end of the black-analysis
. . . . .
O . O . O
. O . O .
O O O O O
Therefore Black controls nothing in the final-position.
white-analysis: Black moves first.
Let us suppose strong Black attacks:
position after Black play 1
# # # # #
. # . # O
# O # O .
O O O O O
position after White play 2
# # # # #
O # . # O
. O # O .
O O O O O
position after Black play 3
# # # # #
O # . # .
. O # O #
O O O O O
position after White play 4
# # # # #
O # O # .
. O . O #
O O O O O
position after Black play 5
# # # # #
. # O # .
# O . O #
O O O O O
position after White play 6
# # # # #
. # O # O
# O . O .
O O O O O
position after Black pass 7
# # # # #
. # O # O
# O . O .
O O O O O
Due to the fixed-ko rule, Black may not capture the middle white ko stone. Due to the basic-ko rule, Black may not capture the right white ko stone.
So far the move-sequence is familiar to us; it agrees to that one that might have occurred during the alternation. Note that move-sequences during the alternation and the white-analysis are considered separately, i.e. prohibitions during the alternation are not considered for the white-analysis.
position after White play 8
. . . . .
O . O . O
. O . O .
O O O O O
position after Black pass 9
. . . . .
O . O . O
. O . O .
O O O O O
position after White play 10
. O . . .
O . O . O
. O . O .
O O O O O
position after Black pass 11
. O . . .
O . O . O
. O . O .
O O O O O
position after White play 12
. O . O .
O . O . O
. O . O .
O O O O O
position after Black pass 13
. O . O .
O . O . O
. O . O .
O O O O O
position after White pass 14
. O . O .
O . O . O
. O . O .
O O O O O
position after Black pass 15
. O . O .
O . O . O
. O . O .
O O O O O
Therefore White controls all intersections in the final-position.
The score is 19 points for White. (Look at the final-position to
calculate the score and recall that Black controls none of the intersections.)
For consistency also the alternation might have got an end with three
successive passes, however, this is not necessary since dead kos are dissolved
during analysis and not already during the alternation; dissolving dead
kos during the alternation would cost points while it is free during analysis.
Besides, if the optional tournament rule "no-result" should be used, in
an alternation ending with three sucessive passes a double ko could be
a cause for a no-result, what does not agree to tradition.
Example with two successive passes ending each analysis (this does not agree with the New Amateur-Japanese Rules):
final-position
. # O . O O
# # # O O .
O O O O . O
white-analysis: Black moves first
. # O 1 O O
# # # O O .
O O O O . O
The moves 2 and 3 are passes. This ends the white-analysis and White cannot control the intersections of the so called dead ko.
(2)
Example with three successive passes ending each analysis (this agrees with the New Amateur-Japanese Rules):
final-position
. # O . O O
# # # O O .
O O O O . O
white-analysis: Black moves first: position after Black play 1
. # . # O O
# # # O O .
O O O O . O
position after White pass 2
. # . # O O
# # # O O .
O O O O . O
The basic-ko rule prohibits White to recapture now. Also White does not want to play as a ko threat.
position after Black pass 3
. # . # O O
# # # O O .
O O O O . O
position after White play 4
. # O . O O
# # # O O .
O O O O . O
The basic-ko rule does not prohibit White to recapture now since the position just before the last opposing move (Black's pass 3) was different.
position after Black pass 5
. # O . O O
# # # O O .
O O O O . O
position after White play 6
O . O . O O
. . . O O .
O O O O . O
position after Black pass 7
O . O . O O
. . . O O .
O O O O . O
position after White play 8
O . O . O O
. O . O O .
O O O O . O
The moves 9, 10, 11 are passes.
In the final-position, White controls also the intersections of
the dead ko. This is possible due to the necessary three successive passes
that end the white-analysis.
It might be tolerated and seen as part of komi that with only one analysis Black would always start and in some final-positions possibly get an advantage from moving first.
Usage of only one analysis has an aesthetic disadvantage: the score
of a position and the negative score of its colour-inverse position need
not be the same for some scarce positions.
Example with only one analysis (this does not agree with the New Amateur-Japanese Rules):
final-position
# # # . O # O O . #
. O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
analysis: Black moves first (always Black starts the analysis)
moves 1 to 4
4 3 # 2 O # O O . #
1 O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
position after Black move 5 (ko capture at 1)
. # . O O # O O . #
# O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
moves 6 to 8
. # 7 O O # O O 6 #
# O O O O # O O 8 #
O O # # # # # O # #
# # # . # . # O # #
position after move 8
. # # . . # O O O .
# . . . . # O O O .
. . # # # # # O . .
# # # . # . # O . .
moves 9 to 18
. # # 13. # O O O .
# . 11. 15# O O O 10
. 9 # # # # # O 12.
# # # . # . # O . 14
The moves 16, 17, 18 are passes.
position at the end of the analysis
. # # # . # O O O .
# . # . # # O O O O
. # # # # # # O O .
# # # . # . # O . O
Black control B and White control W
B B B B B B W W W W
B B B B B B W W W W
B B B B B B B W W W
B B B B B B B W W W
In the final-position, Black controls the intersections of the bent-4-in-the-corner and of his centre group while White controls the intersections of the seki. During the analysis, an exchange takes place. The score is 4 favouring Black. (Recall that the score is calculated in the final-position and that removals during the analysis do not contribute to the score. The analysis is done on a separate board.)
(2)
Like example (1) but the players play a different analysis from move 7:
position after move 6 of the analysis
. # . O O # O O O #
# O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
moves 7 to 10
8 # 10O O # O O O #
# O O O O # O O 7 #
O O # # # # # 9 # #
# # # . # . # O # #
position after move 10
O . O O O # . . . #
. O O O O # . . # #
O O # # # # # # # #
# # # . # . # . # #
moves 11 to 16
O . O O O # . 11. #
. O O O O # 13. # #
O O # # # # # # # #
# # # . # . # . # #
The moves 12, 14, 15, 16 are passes.
Black control B and White control W
W W W W W B B B B B
W W W W W B B B B B
W W B B B B B B B B
B B B B B B B B B B
In the final-position, the score is 8 favouring Black.
So that the reader is not confused, we shall calculate the score in greater detail. To recall, the final-position is:
# # # . O # O O . #
. O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
Black controls 4 empty intersections (making 4 points) and controls 6 white intersections (making 12 points). Altogether Black has 16 points. - White controls 2 empty intersections (making 2 points) and controls 3 black intersections (making 6 points). Altogether White has 8 points. - The difference between both players' scores is 16 - 8 = 8. Black wins by 8 points.
(3)
Like example (1) but the players play a different analysis from move 1:
Black 1, White 2, Black 3 are passes.
position at the end of the analysis
# # # . O # O O . #
. O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
Black control B and White control W
# # # . O B O O . #
. O O O O B O O . #
O O B B B B B O # #
B B B B B B B O # #
White controls nothing. Neither player controls anything in the seki or in the bent-4-in-the-corner since neither player has any immortal stones there.
The score is 2 favouring Black.
Conclusion: Black would force White to play like in example (2) and hence win the game by 8 points.
Alternation: If Black starts the ko, gets the left side,
and White gets the right side, then the score will be 4. If Black starts
the ko, gets the right side, and White gets the left side, then the score
will be 9. If both players pass, then the score will be 8 (see (2)). The
second of these three options is perfect play. Hence alternation should
result in the score 9; in this example, the bent-4-in-the-corner should
be dissolved during the alternation.
Example with two analyses (this agrees with the New Amateur-Japanese Rules):
final-position
# # # . O # O O . #
. O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
black-analysis: White moves first:
moves 1 to 6
5 4 # 3 O # O O . #
2 O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
The move 1 is a pass. The move 6 captures at 2.
position after move 6
. # . O O # O O . #
# O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
moves 7 to 9
. # 8 O O # O O 7 #
# O O O O # O O 9 #
O O # # # # # O # #
# # # . # . # O # #
position after move 9
. # # . . # O O O .
# . . . . # O O O .
. . # # # # # O . .
# # # . # . # O . .
moves 10 to 19
. # # 14. # O O O .
# . 12. 16# O O O .
. 10# # # # # O . .
# # # . # . # O . .
The moves 11, 13, 15, 17, 18, 19 are passes.
Why does White pass so early? The purpose of the black-analysis is to determine what Black controls and only what Black controls. In the black-analysis, White cannot prove to control anything. White proves his control in the white-analysis.
position at the end of the black-analysis
. # # # . # O O O .
# . # . # # O O O .
. # # # # # # O . .
# # # . # . # O . .
Black controls B
B B B B B B O O . #
B B B B B B O O . #
B B B B B B B O # #
B B B B B B B O # #
(Black might have used a different strategy during the black-analysis: passing all the time. This would have been a bad strategy for Black would have controlled only his centre group with its two empty intersections.)
white-analysis: Black moves first
moves 1 to 3
# # # . O # O O . #
. O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
The moves 1, 2, 3 are passes.
position at the end of the white-analysis
# # # . O # O O . #
. O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
White controls W
# # # . O # O O . #
. O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
White controls nothing in the final-position.
(White might have played more aggressively by giving atari everywhere only to be removed everywhere. This strategy during the white-analysis would not have been more successful than passing.)
The score is 18 favouring Black. (In the final-position, Black controls 4 empty intersections and 7 white intersections, which score twice. White controls neither empty intersections nor black intersections.)
With the two analyses (black-analysis and white-analysis, the score agrees to tradition.
(5)
Like example (4) but the players play a different black-analysis:
black-analysis: White moves first:
moves 1 to 9
5 4 8 3 O # O O . #
2 O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
The moves 1, 7, 9 are passes. The move 6 captures at 2.
position after move 11
. # # . . # O O . #
# . . . . # O O . #
. . # # # # # O # #
# # # . # . # O # #
moves 10 to 19
. # # 14. # O O . #
# . 12. 16# O O . #
. 10# # # # # O # #
# # # . # . # O # #
The moves 11, 13, 15, 17, 18, 19 are passes.
position at the end of the black-analysis
. # # # . # O O . #
# . # . # # O O . #
. # # # # # # O # #
# # # . # . # O # #
Black control B
B B B B B B O O . #
B B B B B B O O . #
B B B B B B B O # #
B B B B B B B O # #
Black-score = 18.
(6)
Like example (4) but the players play a different black-analysis:
black-analysis: White moves first: moves 1 to 6
5 4 # 3 O # O O . #
2 O O O O # O O . #
O O # # # # # O # #
# # # . # . # O # #
The move 1 is a pass. The move 6 captures at 2.
moves 7 to 17
9 # 11O O # O 147 #
# O O O O # 12O 8 #
O O # # # # # 10# #
# # # . # . # O # #
The moves 13, 15, 16, 17 are passes.
position at the end of the black-analysis
O . O O O # . # . #
. O O O O # # . # #
O O # # # # # # # #
# # # . # . # . # #
Black control B
# # # . O B B B B B
. O O O O B B B B B
O O B B B B B B B B
B B B B B B B B B B
Black-score = 16.
Conclusion: The players should play the black-analysis and
the white-analysis like in examples (4) or (5). The score should be 18
favouring Black. Note: It would have been a strategic mistake if Black
had played the bent-4-in-the-corner ko fight already during the alternation.
Comparison: One analysis results in the score 8 if the players
ended the alternation too early or in the score 9 otherwise. Two analyses
(the black-analysis and the white-analysis) result in the score 18 if the
players ended the alternation in time; the score coincides with AJT.
final-position
. . . .
# # # #
intersections
a b c d
# # # #
To determine the intersections controlled by Black or White, the black-analysis and then the white-analysis are performed.
***
Black-analysis:
The players choose to play as follows:
O[pbpdppp]
This ends in the following reference position:
. # . #
# # # #
In this reference position, each of the black
stones is immortal. To prove this, White plays the following move-sequence
while Black always passes:
O[ppp]
White does not remove any of the black stones in the reference position.
Now this information is applied to the final-position: In it Black controls each intersection. The reason for this is that in the reference position each intersection is either occupied by an immortal black stone or has immortal black stones on all its adjacent intersections.
***
White-analysis:
The players choose to play as follows:
#[bppp]
This ends in the following reference position:
. # . .
# # # #
In this reference position, there is no white stone. Therefore there is no immortal white stone.
Now this information is applied to the final-position: In it White does not control any intersection. The reason for this is that in the reference position none of the intersections is occupied by an immortal white stone and none has immortal white stones on all its adjacent intersections.
***
To summarize the information about control, we get the following diagram:
Black controls B / White controls W / both players control 2
B B B B
B B B B
This diagram means that each intersection is controlled by Black, none of the intersections is controlled by White, and none of the intersections is controlled by both players.
***
To determine the score, the information about control is applied to the final-position:
final-position
. O # .
O O # #
. O # .
O O # #
. O # .
# O # O
# O # #
intersections
z O # u
O O # #
. O # .
O O # #
a O # d
b O # e
c O # #
To determine the intersections controlled by Black or White, the black-analysis and then the white-analysis are performed.
***
Black-analysis:
The players choose to play as follows:
O[pdppp]
This ends in the following reference position:
. O # .
O O # #
. O # .
O O # #
. O # #
# O # .
# O # #
In this reference position, each of the black
stones on the right side is immortal. Proof: White tries the following
move-sequence while Black always passes:
O[apbpcpzppp]
White does not remove any of the black stones on the right side. The no-suicide rule hinders him. White cannot approach enough liberties of the black stones on the right side. In fact, White cannot occupy even one of their liberties.
Now this information is applied to the final-position: In it Black controls the intersections marked by B in the following diagram. The reason for this is that in the reference position each of these intersections is either occupied by an immortal black stone or has immortal black stones on all its adjacent intersections.
Black controls B:
. O B B
O O B B
. O B B
O O B B
. O B B
# O B B
# O B B
Black does not control the intersections b or c since in the reference position the stones on these intersections are not immortal.
***
White-analysis:
The players choose to play as follows:
#[dacbppeppp]
This ends in the following reference position:
. O # .
O O # #
. O # .
O O # #
O O # #
O O # #
. O # #
In this reference position, each of the white
stones on the left side is immortal. Proof: Black tries the following move-sequence
while White always passes:
#[uppp]
Black does not remove any of the white stones on the left side.
Now this information is applied to the final-position: In it White controls the intersections marked by W in the following diagram. The reason for this is that in the reference position each of these intersections is either occupied by an immortal white stone or has immortal white stones on all its adjacent intersections.
White controls W:
W W # .
W W # #
W W # .
W W # #
W W # .
W W # O
W W # #
White does not control the intersection e since in the reference position the stone on this intersection is not immortal.
***
For convenience, the information about control can also be shown in one diagram:
Black controls B / White controls W / both players control 2
W W B B
W W B B
W W B B
W W B B
W W B B
W W B B
W W B B
***
To determine the score, the information about control is applied to the final-position:
final-position
. O O O .
# # # # #
intersections
a O O O b
# # # # #
To determine the intersections controlled by Black or White, the black-analysis and then the white-analysis are performed.
***
Black-analysis:
The players choose to play as follows:
O[ppp]
This ends in the following reference position:
. O O O .
# # # # #
In this reference position, none of the black
stones is immortal:
O[apbppp]
White removes each of the black stones in the reference position. Therefore none of these black stones is immortal.
Now this information is applied to the final-position: In it Black does not control any intersection. The reason for this is that in the reference position none of the intersections is occupied by an immortal black stone and none has immortal black stones on all its adjacent intersections.
***
White-analysis:
The players choose to play as follows:
#[pabppp]
This ends in the following reference position:
. . . . #
# # # # #
In this reference position, there is no white stone. Therefore there is no immortal white stone.
Now this information is applied to the final-position: In it White does not control any intersection. The reason for this is that in the reference position none of the intersections is occupied by an immortal white stone and none has immortal white stones on all its adjacent intersections.
***
The information about control can be summarized in the following diagram:
Black controls B / White controls W / both players control 2
. O O O .
# # # # #
I.e., none of the intersections is controlled by Black, controlled by White, or even controlled by both players.
***
To determine the score, the information about control is applied to the final-position:
One class of examples
with unexpected scores has the frequency scarce: 1000-year-ko and seki
elsewhere on the board. This is the price for having applicable
Japanese style rules. - By adding further definitions and rules (about
"ko-pass"), such examples would have expected scores but at the same time
most players and referees would not be able to apply the rules correctly.
This is the experience during referee workshops in that the author taught
rules of play.
The following is an extract of some of the possible rules additions for "ko-pass". Because of the third move type other definitions must also be changed, what is not shown here.
The following is an extract of some of the possible rules additions for surrounded. This concept is introduced implicitly by describing the connected objects "black-lake" / "whilte-lake" and by using the phrase "adjacent and only adjacent" in the definitions of "black-territory" / "white-territory". The necessary definitions of "black-string" and "white-string" are not shown. Besides the definition of "score" must be changed: "[...] the number of empty intersections that are black-territory [...]".
The following examples
are discussed for NAJ and NAJN.
final-position
. # # O . O
O # # O O .
# O O O O O
# # # # # #
# # # . # .
intersections
a c e O . O
b d f O O .
# O O O O O
# # # # # #
# # # . # .
Black-analysis:
O[pabdcaebfppp]
White-analysis:
#[padcefacbeppp]
Black controls B / White controls W / both players control 2
B W W W W W
B B W W W W
B W W W W W
B B B B B B
B B B B B B
Score = -3.
By coincidence(?!), this agrees to the traditional name and the
score under the Japanese 1949 Rules!
final-position
. O # # . O # .
# # O # . O # .
# # O # # O # .
O O O O O # # .
. . . . O O # #
intersections
a b # # g i # .
c d O # h j # .
e f O # # k # .
O O O O O # # .
. . . . O O # #
Black-analysis:
O[pabdcaegbhfippp]
White-analysis:
#[padcefacbe..]
Black controls B / White controls W / both players control 2
. O B B B B B B
W # W B B B B B
W W W B B B B B
W W W W W B B B
W W W W W W B B
Score = 2.
final-position
O . O # O . #
. O O # O O #
O O O # # O #
# # O O # O .
# # O # # O O
# # # O # # #
. # . O . # .
intersections
O . O # O a b
. O O # O O c
O O O # # O d
# # O O # O e
# # O # # O O
# # # O # # #
h # g O f # z
Black-analysis:
O[paecbagdhf..]
White-analysis:
#[pfgaeppp]
Black controls B / White controls W / both players control 2
W W W B B B B
W W W B B B B
W W W B B B B
# # W W B B B
# # W B B B B
# # # O B B B
. # . O B B B
score = 16
[Acknowledgement: Ing Chang-ki]
final-position
. # # # # #
# # . # O #
O O # O . O
. O O O O O
O # # # # #
# # . # . #
# # # # # #
O O O O O O
O O . O . O
intersections
z # # # # #
# # c # e #
O O d O f O
a O O O O O
b # # # # #
# # . # . #
# # # # # #
O O O O O O
O O . O . O
Black-analysis:
One of:
O[pacbzppp]
O[pfcaedbppacbzppp]
White-analysis:
One of:
#[acfbdepcfpaedbfcpedppp]
#[acfbdepcfppedpfcaedbppp]
#[acfbdeppfcaedbpcfppedppp]
Black controls B / White controls W / both players control 2
. # # # # #
# # . # O #
O O # O . O
B O O O O O
B B B B B B
B B B B B B
B B B B B B
W W W W W W
W W W W W W
score = 3
final-position
. O O . O . O # . # O
O # # O O O O # # O O
# # . # # O # # O . O
. # # # O # # # # O O
# # O O O O O # # . O
O O O . O . O # # # O
intersections
b c d e O f O # g h O
a # # O O O O # # O O
# # . # # O # # i j O
. # # # O # # # # O O
# # O O O O O # # k O
O O O . O . O # # # O
Black-analysis:
O[pbgedckepdppp]
White-analysis:
#[pgjppihppp]
Black controls B / White controls W / both players control 2
B B B B O . O # . # O
B B B O O O O # # O O
B B B B B O # # O . O
B B B B W # # # # O O
B B W W W W W # # . O
W W W W W W W # # # O
score = 8
Notes: The concept controls under the basic-fixed-ko rules produces
an unexpected result. However, this result is pretty meaningful because
it indicates how far Black can approach the shape. The same applies if
the basic-ko rule is the only ko rule.
final-position
# # # . O # . # O
. O O O O # # O O
O O O O O # O . O
. O O O O # # O O
O # # # O # # . O
# # # # # O # # #
. # . # O O O O O
# # # # O O . O .
intersections
d e f g O # h i O
c O O O O # # O O
O O O O O # j k O
b O O O O # # O O
a # # # O # # l O
# # # # # O # # #
. # . # O O O O O
# # # # O O . O .
Black-analysis:
O[pcgedchkdbfappp]
White-analysis:
#[pcpgehkpjippp]
Black controls B / White controls W / both players control 2
# # # . O # . # O
. O O O O # # O O
O O O O O # O . O
B O O O O # # O O
B B B B O # # . O
B B B B B W # # #
B B B B W W W W W
B B B B W W W W W
score = 3
final-position
. O . # O . O #
O # # # O O # #
. # O O O # . #
# # O O O O # #
O O O O O O . #
intersections
c d e # O f g #
b # # # O O # #
a # O O O h i #
# # O O O O # #
O O O O O O j #
Black-analysis:
O[pfiphgaeppp]
White-analysis:
#[pcfipaebhgcdfa..]
Black controls B / White controls W / both players control 2
W W W W W W W W
W W W W W W W W
W W W W W W W W
W W W W W W W W
W W W W W W W W
score = -36
alternation, White to move just after Black's ko-capture
O O O # O .
. O # . # O
O O # # # #
. O # . # .
intersections
O O O a c d
. O # b # e
O O # # # #
. O # . # .
Alternation:
O[pdpp]
final-position: prisoner-difference = 2
O O O # . #
. O # . # .
O O # # # #
. O # . # .
Black-analysis:
O[ppp]
White-analysis:
#[ppp]
Black controls B / White controls W / both players control 2
W W W B B B
W W B B B B
W W B B B B
W W B B B B
score = 5
alternation, White to move just after Black's ko-capture
O . O O # O .
. . O # . # O
O . O # # # #
. # O # . # .
intersections
O . O O c O e
. a O # d # f
O b O # # # #
z # O # . # .
NAJ, NAJN:
O[pp] is legal.
Black-analysis:
O[dabcpeppp]
White-analysis:
#[ebpapzppp]
score = 1
J2003:
O[pp] is illegal.
O[pepp].
score = 0
[Acknowledgement: Robert Pauli]
Black to move during the alternating-sequence
# # . O # . # O . O # . O
# # O O # # # O O O # # O
# . # O # . # O . O # O O
# # O O # # # O O O # O .
# O . O # # # O O O # # O
intersections
# # . O # . # O . O # z O
# # O O # # # O O O # # O
# a a O # . # O . O # O O
# # O O # # # O O O # O k
# a a O # # # O O O # # k
NAJN:
Alternation:
One of:
#[kaakaa]
#[kaakaa]*[kaakaa]
The players would agree or the referee would let the players agree to end the game in a no-result.
***
NAJ:
Alternation:
One of:
#[pp]
#[aakaakpp]
#[kaakaapp]
final-position
# # . O # . # O . O # . O
# # O O # # # O O O # # O
# . # O # . # O . O # O O
# # O O # # # O O O # O .
# O . O # # # O O O # # O
Black-analysis:
O[zaapaappp]
White-analysis:
One of:
#[pz..]
#[aakaakpz..]
#[kaakaapz..]
Black controls B / White controls W / both players control 2
# # . O B B B W W W W W W
# # O O B B B W W W W W W
# . # O B B B W W W W W W
# # O O B B B W W W W W W
# O . O B B B W W W W W W
score = -16
Notes: Other positions like 1) double-ko-death and fighting-ko or
2) double-ko-seki and dead-ko (also known as moonshine-life) agree to AJT.
Black to move during the alternation:
O O O O O
. O . O #
O # O # .
# # # # #
intersections
O O O O O
a O c O e
b # d # f
# # # # #
NAJN:
Alternation:
One of:
#[afcbed]
#[afcbed]*[afcbed]
The players would agree or the referee would let the players agree to end the game in a no-result.
***
NAJ:
Alternation:
One of:
#[pp]
#[afcbedpp]
Black-analysis:
O[fppp]
White-analysis:
#[afcbedpf..]
Black controls B / White controls W / both players control 2
W W W W W
W W W W W
W W W W W
W W W W W
score = -19
Black to move during the alternation:
. O . # . O # . .
# O O O # # O O O
# # # # # O O . O
O O O O O O . O O
intersections
e f a b c d j k l
# g h i # # O O O
# # # # # O O . O
O O O O O O . O O
NAJN:
Alternation:
One of:
#[acbd]
#[acbd]*[acbd]
The players would agree or the referee would let the players agree to end the game in a no-result.
***
NAJ:
Alternation:
One of:
#[pp]
#[acbdpp]
etc.
Black-anaylsis:
O[a..]
White-analysis:
#[acbdpa..]
Black controls B / White controls W / both players control 2
W W W W W W W W W
W W W W W W W W W
W W W W W W W W W
W W W W W W W W W
score = -27
How frequent are 1000-year kos with a not connected ko stone at the end of the alternation? A non-representative database query at gobase.org gives 36 games with a 1000-year ko in the corner. Of them 18 were resigned, 18 counted. Of the 18 counted games the database server permitted replaying 9 the games. 1 game used Chinese rules (not interesting since under Area Scoring rules a 1000-year ko can be dissolved until the end of the alternation) and 8 games used Japanese style rules. Among these 8 counted games under Japanese rules, in 8 games the 1000-year ko was dissolved due to a ko fight or connected to avoid a ko fight (rather than just to simplify scoring) before the end of alternation. In 0 of these 8 games the 1000-year ko was left unconnected at the end of alternation. Hence quite likely a game with a strategically correctly unconnected 1000-year ko at the of the alternation is rare.
Not each final-position with an unconnected 1000-year ko is hot under NAJ; there must also be some suitable ko threats on the board. Furthermore, not necessarily each position must involve significantly different strategies during the alternation under NAJ and AJT. By the way, it is not particularly clear how AJT treat 1000-year ko at the end of the alternation, except that the World Amateur Go Championship Rules provide a precedental ruling.
Other kos than 1000-year kos that are indirect (in some traditional meaning) and remain unconnected at the end of the alternation might also lead to different strategies under NAJ and under AJT in some final-positions with suitable ko threats. One such other shape is bent-5-in-the-corner. However, presumably such shapes are even rarer than 1000-year ko.
As an additional remark, the Korean Baduk Association's Rules of 1992 have a precedental ruling for indirect kos. Korean professionals do not understand that rule: Every professional that is aware of that rule at all has a different opinion on what that rule might mean.
Concluding, hardly it is a too great luxury of NAJ that unconnected
1000-year ko at the end of the alternation might sometimes lead to a non-traditional
score. It would be an overkill to modify NAJ just because of undissolved
indirect kos.
final-position with connected ko stone
# # # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Score = 2.
final-position with ko stone of the ko's possible defender
# . # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
black-analysis: variation 1
moves 1 to 6 (White moves first)
# 3 # 2 O # . # O # #
O # # 5 O # # # O 4 #
O O O O O # . # O 6 #
O O O O O # # # O O #
The move 1 is a pass.
position after move 6
. O . . O # . # . # #
O . . O O # # # . # #
O O O O O # . # . # #
O O O O O # # # . . #
moves 7 to 13
. O . . O # . # . # #
O . . O O # # # 10# #
O O O O O # . # . # #
O O O O O # # # 8 . #
The moves 7, 9, 11, 12, 13 are passes.
position at the end of the black-analysis
. O . . O # . # . # #
O . . O O # # # # # #
O O O O O # . # . # #
O O O O O # # # # . #
Black control B
# . # . O B B B B B B
O # # . O B B B B B B
O O O O O B B B B B B
O O O O O B B B B B B
Black-score = 14.
Note: If White answered the ko threat, then Black would control the left side and have a bigger black-score.
black-analysis: variation 2
moves 1 to 3 (White moves first)
# 1 # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
The moves 2, 3 are passes.
moves 4 to 10
4 7 # 6 O # . # O # #
O # # 9 O # # # O 8 #
O O O O O # . # O 10#
O O O O O # # # O O #
The move 5 is a pass. The remaining moves are not shown. The black-score is 14, like in variation 1.
black-analysis: variation 3
moves 1 to 7 (White moves first)
4 1 # 3 O # . # O # #
O # # 6 O # # # O 5 #
O O O O O # . # O 7 #
O O O O O # # # O O #
The move 2 is a pass.
position after move 7
# . # . . # . # O . .
. # # # . # # # O O .
. . . . . # . # O O .
. . . . . # # # O O .
moves 8 to 21
# . # . 18# . # O . .
. # # # . # # # O O .
8 . 12. 16# . # O O .
. 10. 14. # # # O O .
The moves 9, 11, 13, 15, 17, 19, 20, 21 are passes.
position at the end of the black-analysis
# . # . # # . # O . .
. # # # . # # # O O .
# . # . # # . # O O .
. # . # . # # # O O .
Black control B
B B B B B B B B O # #
B B B B B B B B O . #
B B B B B B B B O . #
B B B B B B B B O O #
Black-score = 31.
Conclusion on black-analysis: The players would play the black-analysis either like in variation 1, variation 2, or a similar variation. Then the black-score is 14.
white-analysis:
moves 1 to 4 (Black moves first)
# 1 # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
The moves 2, 3, 4 are passes.
position at the end of the white-analysis
# # # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
White control W
# # # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
White controls nothing.
White-score = 0.
Note: Other variations for the white-analysis are not particularly interesting, either.
Score = black-score - white-score = 14 - 0 = 14.
final-position with ko stone of the ko's possible defender's opponent
. O # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
black-analysis: variation 1
moves 1 to 4 (White moves first)
2 O # 1 O # . # O # #
O # # 4 O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
The move 3 is a pass. The remaining moves are not shown. The black-score is 33.
black-analysis: variation 2
moves 1 to 8 (White moves first)
2 5 # 4 O # . # O # #
O # # 7 O # # # O 6 #
O O O O O # . # O 8 #
O O O O O # # # O O #
The moves 1, 3 are passes.
position after move 8
. O . . O # . # . # #
O . . O O # # # . # #
O O O O O # . # . # #
O O O O O # # # . . #
moves 9 to 15
. O . . O # . # . # #
O . . O O # # # 12# #
O O O O O # . # . # #
O O O O O # # # 10. #
The moves 9, 11, 13, 14, 15 are passes.
position after the end of the black-analysis
. O . . O # . # . # #
O . . O O # # # # # #
O O O O O # . # . # #
O O O O O # # # # . #
Black control B
. O # . O B B B B B B
O # # . O B B B B B B
O O O O O B B B B B B
O O O O O B B B B B B
Black-score = 14.
Conclusion on black-analysis: The players would play the black-analysis like in variation 2. Then the black-score is 14.
white-analysis: variation 1
moves 1 to 6 (Black moves first)
3 O # 2 O # . # O # #
O # # 5 O # # # O 4 #
O O O O O # . # O 6 #
O O O O O # # # O O #
The move 1 is a pass.
position after move 6
# . # . . # . # O . .
. # # # . # # # O O .
. . . . . # . # O O .
. . . . . # # # O O .
moves 7 to 13
# . # . . # . # O . 8
. # # # . # # # O O .
. . . . . # . # O O 10
. . . . . # # # O O .
The moves 7, 9, 11, 12, 13 are passes.
position at the end of the white-analysis
# . # . . # . # O . O
. # # # . # # # O O .
. . . . . # . # O O O
. . . . . # # # O O .
White control W
. O # . O # . # W W W
O # # . O # # # W W W
O O O O O # . # W W W
O O O O O # # # W W W
White-score = 12.
white-analysis: variation 2
moves 1 to 9 (Black moves first)
. O # 2 O # . # O # #
O # 6 4 O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
The moves 1, 3, 5, 7, 8, 9 are passes.
position at the end of the white-analysis
. O . O O # . # W W W
O . O O O # # # W W W
O O O O O # . # W W W
O O O O O # # # W W W
White control W
W W W W W # . # O # #
W W W W W # # # O . #
W W W W W # . # O . #
W W W W W # # # O O #
White-score = 9.
white-analysis: variation 3
moves 1 to 6 (Black moves first)
1 3 # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
The moves 2, 4, 5, 6 are passes.
If White 2 threatened in the seki, then Black would answer, White would capture the ko, Black would pass, White would approach the ko, Black would capture the ko, and White would not have another ko threat. White would control nothing.
position at the end of the white-analysis
# # # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
White control W
. O # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
White controls nothing.
White-score = 0.
Conclusion for white-analysis: If both players play strongly, then the white-score is 0.
Score = black-score - white-score = 14 - 0 = 14.
position with Black to move during the alternation and with ko stone of the ko's possible defender
# . # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Variation 1: If Black connects and then both players pass, the score will be 2.
Variation 2: If Black passes and White passes, the score will be 14.
Variation 3: If Black passes, then White captures the ko, and then both players pass, the board-score will be 0, White will have 1 prisoner, so the score will be -1. (White could play more aggressively with move 4 but Black would benefit.)
Variation 4:
moves 1 to 7
# 2 # 1 O # . # O # #
O # # 4 O # # # O 3 #
O O O O O # . # O 5 #
O O O O O # # # O O #
The moves 6, 7 are passes.
position at the end of the alternation
. O . . O # . # . # #
O . . O O # # # . # #
O O O O O # . # . # #
O O O O O # # # . . #
The board-score is 2. The prisoner-difference is 0. The score is 2.
Conclusion:
Variation 1 or 4 are perfect play. The score is 2.
position with White to move during the alternation and with ko stone of the ko's possible defender
# . # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Variation 1: If White passes, then Black connects, and then both players pass, the score will be 2.
Variation 2: If White passes and Black passes, the score will be 14.
Variation 3: If White captures the ko, and then both players pass, the board-score will be 0, White will have 1 prisoner, so the score will be -1. (Black could play more aggressively with move 2 but White would benefit. White could play more aggressively with move 3 but Black would benefit.)
Variation 4: If White passes and Black attacks like in (1.4), variation 4, then the score will be 2.
Conclusion:
Variation 3 is perfect play. The score is -1. (Compare the analysis
for the final-position with a white ko stone, see (1.3).)
position with Black to move during the alternation and with ko stone of the ko's possible defender's opponent
. O # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Variation 1: If both players pass, then the score is 0. (Compare (1.5), variation 3.)
Variation 2:
moves 1 to 6
1 4 # . O # . # O # #
O # # . O # # # O 2 #
O O O O O # . # O 3 #
O O O O O # # # O O #
The moves 5, 6 are passes.
position at the end of the alternation
. O # . O # . # . # #
O # # . O # # # . # #
O O O O O # . # . # #
O O O O O # # # . . #
The board-score (Black controls the middle and right side while White controls nothing) is 7. The prisoner-difference is 5. The score is 12.
Variation 3:
moves 1 to 8
1 4 # 3 O # . # O # #
O # # 6 O # # # O 2 #
O O O O O # . # O 5 #
O O O O O # # # O O #
The moves 7, 8 are passes.
position at the end of the alternation
. O . . O # . # . # #
O . . O O # # # . . #
O O O O O # . # . # #
O O O O O # # # . . #
The board-score is 3. The prisoner-difference is 2. The score is 5.
Variation 4:
moves 1 to 3
1 O # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
The moves 2, 3 are passes. The board-score is 14 (see (1.2)). The prisoner-difference is 1. The score is 15.
Variation 5:
moves 1 to 9
1 4 # 3 O # . # O # #
O # # 6 O # # # O 5 #
O O O O O # . # O 7 #
O O O O O # # # O O #
The moves 2, 8, 9 are passes.
position at the end of the alternation
. O . . O # . # . # #
O . . O O # # # . # #
O O O O O # . # . # #
O O O O O # # # . . #
The board-score is 2. The prisoner-difference is 1. The score is 3.
Conclusion:
Variation 2 is perfect play. The score is 12.
position with White to move during the alternation and with ko stone of the ko's possible defender's opponent
. O # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Variation 1: If both players pass, then the score is 0. (Compare (1.5), variation 3.)
Variation 2: If White passes, Black captures the ko, and then both players pass, then the score is 15. (Compare (1.2).)
Variation 3: White passes, then see (1.6), variation 2. The score is 12.
Variation 4: White approaches the ko, etc. This results in Black getting the left and White the right side. The score is 22.
Conclusion: Variation 3 is perfect play. The score is 12.
Summary for NAJ:
If during the alternation the position starts with a black ko stone, then the score is 2 or -1, depending on whether Black or White moves first.
If during the alternation the position starts with a white ko stone,
then in the final-position the right side's seki will be dissolved in Black's
favour and the 1000-year ko remains with a white ko stone on the board.
The score is 12.
Score under AJT:
(Recall that AJT stands for "Amateur-Japanese rules tradition".)
Since it is unclear how AJT treats a 1000-year ko, several possible interpretations must be studied.
Interpretation A: Like under World Amateur Go Championship Rules.
Since the players have not fought the ko, Black must connect the 1000-year ko. If necessary, just before Black must capture the ko. A precedental ruling for 1000-year kos says so.
final-position
# # # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Board-score = 2. Prisoner-difference: 0 or 1, depending on whether a black or white ko stone was in the ko until just before the end of the alternation. Score: 2 or 3, depending on the same.
Interpretation B: Naive assessment of life, death, and territory.
final-position with a black ko stone
# . # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Without clear reasoning, naive assessment assigns the status "alive" to each string, identifies two sekis, and claims the score 2.
final-position with a white ko stone
. O # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Without clear reasoning, naive assessment fails to assign status to the ko stone and the black string adjacent to it, assigns the status "alive" to each other string, identifies two sekis, and claims the score 2.
Comment: The advantage of naivity is speed unless a referee is called.
Interpretation C: Some (partially) formal Japanese style ruleset is used, be it either the Japanese 2003 Rules or the Japanese 1989 Rules with the Japanese 2003 Rules as their backup.
Application of the Japanese 2003 Rules to the example position requires so much space that it is beyond the scope of this webpage. To state just the conclusion: The score is 2, regardless of which ko stone is in the ko.
Summary: For the sake of keeping this webpage readable, we
shall ignore the strategic variety under interpretation A and assume AJT
to produce the score 2.
AJT: position with Black to move during the alternation and with ko stone of the ko's possible defender
# . # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Variation 1: If Black connects and then both players pass, the score will be 2.
Variation 2: If Black passes and White passes, the score will be 2.
Variation 3: If Black passes, then White captures in the ko, and then both players pass, the board-score will be 2, White will have 1 prisoner, so the score will be 1. (White could play more aggressively with move 4 but Black would benefit.)
Variation 4:
moves 1 to 7
# 2 # 1 O # . # O # #
O # # 4 O # # # O 3 #
O O O O O # . # O 5 #
O O O O O # # # O O #
The moves 6, 7 are passes.
position at the end of the alternation
. O . . O # . # . # #
O . . O O # # # . # #
O O O O O # . # . # #
O O O O O # # # . . #
The board-score is 2. The prisoner-difference is 0. The score is 2.
Conclusion:
Variation 1, variation 4, or a similar variation are perfect play.
The score is 2.
AJT: position with White to move during the alternation and with ko stone of the ko's possible defender
# . # . O # . # O # #
O # # . O # # # O . #
O O O O O # . # O . #
O O O O O # # # O O #
Variation 1: If White passes, Black connects, and both players pass, the score will be 2.
Variation 2: If White passes and Black passes, the score will be 2.
Variation 3: If White captures in the ko, Black passes, and White passes, then the score will be 1.
Variation 4:
moves 1 to 7
# 3 # 2 O # . # O # #
O # # 5 O # # # O 4 #
O O O O O # . # O 6 #
O O O O O # # # O O #
The moves 1, 7, 8 are passes.
position at the end of the alternation
. O . . O # . # . # #
O . . O O # # # . # #
O O O O O # . # . # #
O O O O O # # # . . #
The board-score is 2. The prisoner-difference is 0. The score is 2.
Conclusion:
Variation 3 is perfect play and the score will be 1.
AJT: The other cases during the alternation shall be an excercise
for the reader.
Comparison of NAJ and AJT:
As (1.5) and (1.11) show, in some positions with 1000-year ko and
ko threats strategies during the alternation, perfect play, and correct
scores can differ between NAJ and AJT. Strategies and perfect play differ
because the scores of some of the possible final-positions differ.